On normalizers in some Coxeter groups

Let $G$ be a finitely generated Coxeter group with presentation
$$G=< a_1,\ldots, a_n;(a_ia_j)^{m_{ij}}=1,   i,j =\overline{1,n} >,$$
where $m_{ij}$ — are the elements of the symmetric Coxeter matrix: $\forall i,j \in\overline{1,n},  m_{ii}=1, m_{ij} \geq$ $ \geq2,   i\ne j$.
If $m_{ij}\geq3$ $(m_{ij}>3)$, $i\ne j$, then $G$ is a Coxeter group of large (extra-large) type. These groups introduced by K. Appel and P. Schupp.
If the group $G$ corresponds to a finite tree-graph $\Gamma$ such that if the vertices of some edge $e$ of the graph $\Gamma$ correspond to generators $a_i, a_j$, then the edge $e$ corresponds to the ratio of the species $(a_ia_j)^{m_{ij}}=1$, then $G$ is a Coxeter group with a tree-structure.
Coxeter groups with a tree-structure introduced by V. N. Bezverkhnii, algorithmic problems in them was considered by V. N. Bezverkhnii and O. V. Inchenko.
The group $G$ can be represented as tree product 2-generated of Coxeter groups, amalgamated by cyclic subgroups. Thus from the graph $\Gamma$ of $G$ will move to the graph $\overline{\Gamma}$ in the following way: the vertices of the graph $\overline{\Gamma}$ we will put in line Coxeter group on two generators
$$G_{ij} = <a_i, a_j; a_i^2=a_j^2=1,(a_ia_j)^{m_{ij}}=1>$$
and
$$G_{jk} = <a_j, a_k; a_j^2=a_k^2=1,(a_ja_k)^{m_{jk}}=1>,$$
to every edge $\overline{e}$ joining the vertices corresponding to $G_{ij}$ and $G_{jk}$ is a cyclic subgroup
$$<a_j;a_j^2=1>.$$

In this paper we prove the following theorem: normalizer of finitely generated subgroup of Coxeter group with tree-structure
$$\overline{G}=G_{ij}\ast_{<a_j; a_j^2>}G_{jk},$$

$$G_{ij} = <a_i, a_j; a_i^2=a_j^2=1,(a_ia_j)^{m_{ij}}=1>,$$

$$G_{jk} = <a_j, a_k; a_j^2=a_k^2=1,(a_ja_k)^{m_{jk}}=1>$$
finitely generated and exist algorithm for generating.
Bibliography: 18 titles.