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Probl. Anal. Issues Anal., 2020, Volume 9(27), Issue 3, Pages 119–130 (Mi pa310)  

On finding the resultant of two entire functions

A. M. Kytmanova, E. K. Myshkinab

a Siberian Federal University, 660041, 79, Svobodny pr., Krasnoyarsk, Russia
b Institute of Computational Modelling, SB RAS, 660036, 50/44, Akademgorodok, Krasnoyarsk, Russia

Abstract: Using Newton's recurrent formulae, we find the product of values of an entire function of one variable in zeroes of another entire function. This allows to answer whether they have common zeros. By that, we propose an approach to construction of the resultant of two entire functions. We also give examples illustrating the main result.

Keywords: resultant, entire function, Newton formulae.

Funding Agency Grant Number
Ministry of Science and Higher Education of the Russian Federation 075-02-2020-1534/1
Russian Foundation for Basic Research 19-31-60012
The first author was supported by Krasnoyarsk Mathematical Center and financed by the Ministry of Science and Higher Education of the Russian Federation in the framework of the establishment and development of regional Centers for Mathematics Research and Education (Agreement No. 075-02-2020-1534/1), the second author was supported by the RFBR (grant 19-31-60012).


DOI: https://doi.org/10.15393/j3.art.2020.8571

Full text: PDF file (486 kB)
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Bibliographic databases:

UDC: 517.55
MSC: 13P15, 32A15
Received: 29.05.2020
Revised: 16.08.2020
Accepted:16.08.2020
Language:

Citation: A. M. Kytmanov, E. K. Myshkina, “On finding the resultant of two entire functions”, Probl. Anal. Issues Anal., 9(27):3 (2020), 119–130

Citation in format AMSBIB
\Bibitem{KytMys20}
\by A.~M.~Kytmanov, E.~K.~Myshkina
\paper On finding the resultant of two entire functions
\jour Probl. Anal. Issues Anal.
\yr 2020
\vol 9(27)
\issue 3
\pages 119--130
\mathnet{http://mi.mathnet.ru/pa310}
\crossref{https://doi.org/10.15393/j3.art.2020.8571}
\isi{http://gateway.isiknowledge.com/gateway/Gateway.cgi?GWVersion=2&SrcApp=PARTNER_APP&SrcAuth=LinksAMR&DestLinkType=FullRecord&DestApp=ALL_WOS&KeyUT=000590954400007}


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